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(3x-2)(4x+20)=0
We multiply parentheses ..
(+12x^2+60x-8x-40)=0
We get rid of parentheses
12x^2+60x-8x-40=0
We add all the numbers together, and all the variables
12x^2+52x-40=0
a = 12; b = 52; c = -40;
Δ = b2-4ac
Δ = 522-4·12·(-40)
Δ = 4624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4624}=68$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(52)-68}{2*12}=\frac{-120}{24} =-5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(52)+68}{2*12}=\frac{16}{24} =2/3 $
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