2y+11=4(y-2)

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Solution for 2y+11=4(y-2) equation: 



2y+11=4(y-2)

We move all terms to the left:

2y+11-(4(y-2))=0



We calculate terms in parentheses: -(4(y-2)), so:

4(y-2)

We multiply parentheses

4y-8

Back to the equation:

-(4y-8)



We get rid of parentheses

2y-4y+8+11=0

We add all the numbers together, and all the variables

-2y+19=0

We move all terms containing y to the left, all other terms to the right

-2y=-19

y=-19/-2

y=9+1/2

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