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5/8p+1/4p=2
We move all terms to the left:
5/8p+1/4p-(2)=0
Domain of the equation: 8p!=0
p!=0/8
p!=0
p∈R
Domain of the equation: 4p!=0We calculate fractions
p!=0/4
p!=0
p∈R
20p/32p^2+8p/32p^2-2=0
We multiply all the terms by the denominator
20p+8p-2*32p^2=0
We add all the numbers together, and all the variables
28p-2*32p^2=0
Wy multiply elements
-64p^2+28p=0
a = -64; b = 28; c = 0;
Δ = b2-4ac
Δ = 282-4·(-64)·0
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{784}=28$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-28}{2*-64}=\frac{-56}{-128} =7/16 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+28}{2*-64}=\frac{0}{-128} =0 $
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