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6(x+4)+4=8x-2(x-3)
We move all terms to the left:
6(x+4)+4-(8x-2(x-3))=0
We multiply parentheses
6x-(8x-2(x-3))+24+4=0
We calculate terms in parentheses: -(8x-2(x-3)), so:We add all the numbers together, and all the variables
8x-2(x-3)
We multiply parentheses
8x-2x+6
We add all the numbers together, and all the variables
6x+6
Back to the equation:
-(6x+6)
6x-(6x+6)+28=0
We get rid of parentheses
6x-6x-6+28=0
We add all the numbers together, and all the variables
22!=0
There is no solution for this equation
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