5/8(-6-3x)=10/4(12-6x)

Solution for 5/8(-6-3x)=10/4(12-6x) equation:

5/8(-6-3x)=10/4(12-6x)

We move all terms to the left:

5/8(-6-3x)-(10/4(12-6x))=0


Domain of the equation: 8(-6-3x)!=0

x∈R



Domain of the equation: 4(12-6x))!=0

x∈R


We add all the numbers together, and all the variables

5/8(-3x-6)-(10/4(-6x+12))=0

We calculate fractions


(20x(-)/(8(-3x-6)*4(-6x+12)))+(-80x0/(8(-3x-6)*4(-6x+12)))=0


We calculate terms in parentheses: +(20x(-)/(8(-3x-6)*4(-6x+12))), so:

20x(-)/(8(-3x-6)*4(-6x+12))

We add all the numbers together, and all the variables

20x0/(8(-3x-6)*4(-6x+12))

We multiply all the terms by the denominator


20x0

We add all the numbers together, and all the variables

20x

Back to the equation:

+(20x)



We calculate terms in parentheses: +(-80x0/(8(-3x-6)*4(-6x+12))), so:

-80x0/(8(-3x-6)*4(-6x+12))

We multiply all the terms by the denominator


-80x0

We add all the numbers together, and all the variables

-80x

Back to the equation:

+(-80x)


We get rid of parentheses

20x-80x=0

We add all the numbers together, and all the variables

-60x=0

x=0/-60

x=0