2(3y-9)=-7(y+1)

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Solution for 2(3y-9)=-7(y+1) equation: 



2(3y-9)=-7(y+1)

We move all terms to the left:

2(3y-9)-(-7(y+1))=0

We multiply parentheses

6y-(-7(y+1))-18=0



We calculate terms in parentheses: -(-7(y+1)), so:

-7(y+1)

We multiply parentheses

-7y-7

Back to the equation:

-(-7y-7)



We get rid of parentheses

6y+7y+7-18=0

We add all the numbers together, and all the variables

13y-11=0

We move all terms containing y to the left, all other terms to the right

13y=11

y=11/13

y=11/13

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