5/7x-4=1/7(x+14

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Solution for 5/7x-4=1/7(x+14 equation: 



5/7x-4=1/7(x+14

We move all terms to the left:

5/7x-4-(1/7(x+14)=0



Domain of the equation: 7x!=0

x!=0/7

x!=0

x∈R





Domain of the equation: 7(x+14)-4!=0

We move all terms containing x to the left, all other terms to the right

7(x+14)!=4

x∈R



We calculate fractions


(35x(x-4)/(49x^2(x-4)+(-(1*7x)/(49x^2(x-4)=0



We calculate terms in parentheses: +(35x(x-4)/(49x^2(x-4)+(-(1*7x)/(49x^2(x-4), so:

35x(x-4)/(49x^2(x-4)+(-(1*7x)/(49x^2(x-4

We can not solve this equation

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