(-4a+1)(-2-6a)=0

Solution for (-4a+1)(-2-6a)=0 equation:

(-4a+1)(-2-6a)=0

We add all the numbers together, and all the variables

(-4a+1)(-6a-2)=0

We multiply parentheses ..

(+24a^2+8a-6a-2)=0

We get rid of parentheses

24a^2+8a-6a-2=0

We add all the numbers together, and all the variables

24a^2+2a-2=0

a = 24; b = 2; c = -2;
Δ = b2-4ac
Δ = 22-4·24·(-2)
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-14}{2*24}=\frac{-16}{48}
=-1/3
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+14}{2*24}=\frac{12}{48}
=1/4
$