5/7(z+2)=6

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Solution for 5/7(z+2)=6 equation: 



5/7(z+2)=6

We move all terms to the left:

5/7(z+2)-(6)=0



Domain of the equation: 7(z+2)!=0

z∈R



We multiply all the terms by the denominator


-6*7(z+2)+5=0

Wy multiply elements

-42z(z+5=0

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