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6x+2(x-5)=4(2x-4)
We move all terms to the left:
6x+2(x-5)-(4(2x-4))=0
We multiply parentheses
6x+2x-(4(2x-4))-10=0
We calculate terms in parentheses: -(4(2x-4)), so:We add all the numbers together, and all the variables
4(2x-4)
We multiply parentheses
8x-16
Back to the equation:
-(8x-16)
8x-(8x-16)-10=0
We get rid of parentheses
8x-8x+16-10=0
We add all the numbers together, and all the variables
6!=0
There is no solution for this equation
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