5/7(x+1)=1/21(x+2)

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Solution for 5/7(x+1)=1/21(x+2) equation: 



5/7(x+1)=1/21(x+2)

We move all terms to the left:

5/7(x+1)-(1/21(x+2))=0



Domain of the equation: 7(x+1)!=0

x∈R





Domain of the equation: 21(x+2))!=0

x∈R



We calculate fractions


(105xx/(7(x+1)*21(x+2)))+(-7xx/(7(x+1)*21(x+2)))=0



We calculate terms in parentheses: +(105xx/(7(x+1)*21(x+2))), so:

105xx/(7(x+1)*21(x+2))

We multiply all the terms by the denominator


105xx

Back to the equation:

+(105xx)





We calculate terms in parentheses: +(-7xx/(7(x+1)*21(x+2))), so:

-7xx/(7(x+1)*21(x+2))

We multiply all the terms by the denominator


-7xx

Back to the equation:

+(-7xx)



We get rid of parentheses

105xx-7xx=0

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