5/7(t+7)=2/7t+27

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Solution for 5/7(t+7)=2/7t+27 equation: 



5/7(t+7)=2/7t+27

We move all terms to the left:

5/7(t+7)-(2/7t+27)=0



Domain of the equation: 7(t+7)!=0

t∈R





Domain of the equation: 7t+27)!=0

t∈R



We get rid of parentheses

5/7(t+7)-2/7t-27=0

We calculate fractions


35t/(49t^2+343t)+(-14tt/(49t^2+343t)-27=0

We calculate fractions

We do not support etpression: t^3

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