1x+2x+3+3=3(1x+2)

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Solution for 1x+2x+3+3=3(1x+2) equation: 



1x+2x+3+3=3(1x+2)

We move all terms to the left:

1x+2x+3+3-(3(1x+2))=0

We add all the numbers together, and all the variables

1x+2x-(3(x+2))+3+3=0

We add all the numbers together, and all the variables

3x-(3(x+2))+6=0



We calculate terms in parentheses: -(3(x+2)), so:

3(x+2)

We multiply parentheses

3x+6

Back to the equation:

-(3x+6)



We get rid of parentheses

3x-3x-6+6=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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