2z+3-4=3z-5-2

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Solution for 2z+3-4=3z-5-2 equation: 



2z+3-4=3z-5-2

We move all terms to the left:

2z+3-4-(3z-5-2)=0

We add all the numbers together, and all the variables

2z-(3z-7)+3-4=0

We add all the numbers together, and all the variables

2z-(3z-7)-1=0

We get rid of parentheses

2z-3z+7-1=0

We add all the numbers together, and all the variables

-1z+6=0

We move all terms containing z to the left, all other terms to the right

-z=-6

z=-6/-1

z=+6

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