x+3(x+2)=8+2(x+6)

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Solution for x+3(x+2)=8+2(x+6) equation: 



x+3(x+2)=8+2(x+6)

We move all terms to the left:

x+3(x+2)-(8+2(x+6))=0

We multiply parentheses

x+3x-(8+2(x+6))+6=0



We calculate terms in parentheses: -(8+2(x+6)), so:

8+2(x+6)

determiningTheFunctionDomain
2(x+6)+8

We multiply parentheses

2x+12+8

We add all the numbers together, and all the variables

2x+20

Back to the equation:

-(2x+20)



We add all the numbers together, and all the variables

4x-(2x+20)+6=0

We get rid of parentheses

4x-2x-20+6=0

We add all the numbers together, and all the variables

2x-14=0

We move all terms containing x to the left, all other terms to the right

2x=14

x=14/2

x=7

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