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5/6x-3=2x-5
We move all terms to the left:
5/6x-3-(2x-5)=0
Domain of the equation: 6x!=0We get rid of parentheses
x!=0/6
x!=0
x∈R
5/6x-2x+5-3=0
We multiply all the terms by the denominator
-2x*6x+5*6x-3*6x+5=0
Wy multiply elements
-12x^2+30x-18x+5=0
We add all the numbers together, and all the variables
-12x^2+12x+5=0
a = -12; b = 12; c = +5;
Δ = b2-4ac
Δ = 122-4·(-12)·5
Δ = 384
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{384}=\sqrt{64*6}=\sqrt{64}*\sqrt{6}=8\sqrt{6}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-8\sqrt{6}}{2*-12}=\frac{-12-8\sqrt{6}}{-24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+8\sqrt{6}}{2*-12}=\frac{-12+8\sqrt{6}}{-24} $
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