5/4x+3=3/3x+4

Solution for 5/4x+3=3/3x+4 equation:

5/4x+3=3/3x+4

We move all terms to the left:

5/4x+3-(3/3x+4)=0


Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R



Domain of the equation: 3x+4)!=0

x∈R


We get rid of parentheses

5/4x-3/3x-4+3=0

We calculate fractions


15x/12x^2+(-12x)/12x^2-4+3=0

We add all the numbers together, and all the variables

15x/12x^2+(-12x)/12x^2-1=0

We multiply all the terms by the denominator


15x+(-12x)-1*12x^2=0

Wy multiply elements

-12x^2+15x+(-12x)=0

We get rid of parentheses

-12x^2+15x-12x=0

We add all the numbers together, and all the variables

-12x^2+3x=0

a = -12; b = 3; c = 0;
Δ = b2-4ac
Δ = 32-4·(-12)·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3}{2*-12}=\frac{-6}{-24}
=1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3}{2*-12}=\frac{0}{-24}
=0
$