(2/3)(3p-5)=(4/9)

Solution for (2/3)(3p-5)=(4/9) equation:

(2/3)(3p-5)=(4/9)

We move all terms to the left:

(2/3)(3p-5)-((4/9))=0


Domain of the equation: 3)(3p-5)!=0

p∈R


We add all the numbers together, and all the variables

(+2/3)(3p-5)-((+4/9))=0

We multiply parentheses ..

(+6p^2+2/3*-5)-((+4/9))=0

We calculate fractions


6p^2/()+()/()=0

We add all the numbers together, and all the variables

6p^2/()+1=0

We multiply all the terms by the denominator


6p^2+1*()=0

We add all the numbers together, and all the variables

6p^2=0

a = 6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·6·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$p=\frac{-b}{2a}=\frac{0}{12}=0$