5/4(20x-+12)=-35

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Solution for 5/4(20x-+12)=-35 equation: 



5/4(20x-+12)=-35

We move all terms to the left:

5/4(20x-+12)-(-35)=0



Domain of the equation: 4(20x-+12)!=0

x∈R



We add all the numbers together, and all the variables

5/4(+20x)-(-35)=0

We add all the numbers together, and all the variables

5/4(+20x)+35=0

We multiply all the terms by the denominator


35*4(+20x)+5=0

Wy multiply elements

140x(++5=0

We use the square of the difference formula

140x(+5=0

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