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3(x-3)-13=7+2(x+4)
We move all terms to the left:
3(x-3)-13-(7+2(x+4))=0
We multiply parentheses
3x-(7+2(x+4))-9-13=0
We calculate terms in parentheses: -(7+2(x+4)), so:We add all the numbers together, and all the variables
7+2(x+4)
determiningTheFunctionDomain 2(x+4)+7
We multiply parentheses
2x+8+7
We add all the numbers together, and all the variables
2x+15
Back to the equation:
-(2x+15)
3x-(2x+15)-22=0
We get rid of parentheses
3x-2x-15-22=0
We add all the numbers together, and all the variables
x-37=0
We move all terms containing x to the left, all other terms to the right
x=37
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