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5/3x=10/x+30
We move all terms to the left:
5/3x-(10/x+30)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: x+30)!=0We get rid of parentheses
x∈R
5/3x-10/x-30=0
We calculate fractions
5x/3x^2+(-30x)/3x^2-30=0
We multiply all the terms by the denominator
5x+(-30x)-30*3x^2=0
Wy multiply elements
-90x^2+5x+(-30x)=0
We get rid of parentheses
-90x^2+5x-30x=0
We add all the numbers together, and all the variables
-90x^2-25x=0
a = -90; b = -25; c = 0;
Δ = b2-4ac
Δ = -252-4·(-90)·0
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-25}{2*-90}=\frac{0}{-180} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+25}{2*-90}=\frac{50}{-180} =-5/18 $
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