3(x+1)+2(4x-4)=6

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Solution for 3(x+1)+2(4x-4)=6 equation: 



3(x+1)+2(4x-4)=6

We move all terms to the left:

3(x+1)+2(4x-4)-(6)=0

We multiply parentheses

3x+8x+3-8-6=0

We add all the numbers together, and all the variables

11x-11=0

We move all terms containing x to the left, all other terms to the right

11x=11

x=11/11

x=1

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