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5/3x-6=2/x+2
We move all terms to the left:
5/3x-6-(2/x+2)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: x+2)!=0We get rid of parentheses
x∈R
5/3x-2/x-2-6=0
We calculate fractions
5x/3x^2+(-6x)/3x^2-2-6=0
We add all the numbers together, and all the variables
5x/3x^2+(-6x)/3x^2-8=0
We multiply all the terms by the denominator
5x+(-6x)-8*3x^2=0
Wy multiply elements
-24x^2+5x+(-6x)=0
We get rid of parentheses
-24x^2+5x-6x=0
We add all the numbers together, and all the variables
-24x^2-1x=0
a = -24; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·(-24)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*-24}=\frac{0}{-48} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*-24}=\frac{2}{-48} =-1/24 $
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