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8(x+5)=2(2x+20)+4x
We move all terms to the left:
8(x+5)-(2(2x+20)+4x)=0
We multiply parentheses
8x-(2(2x+20)+4x)+40=0
We calculate terms in parentheses: -(2(2x+20)+4x), so:We get rid of parentheses
2(2x+20)+4x
We add all the numbers together, and all the variables
4x+2(2x+20)
We multiply parentheses
4x+4x+40
We add all the numbers together, and all the variables
8x+40
Back to the equation:
-(8x+40)
8x-8x-40+40=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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