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5/3g=83g=
We move all terms to the left:
5/3g-(83g)=0
Domain of the equation: 3g!=0We add all the numbers together, and all the variables
g!=0/3
g!=0
g∈R
-83g+5/3g=0
We multiply all the terms by the denominator
-83g*3g+5=0
Wy multiply elements
-249g^2+5=0
a = -249; b = 0; c = +5;
Δ = b2-4ac
Δ = 02-4·(-249)·5
Δ = 4980
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4980}=\sqrt{4*1245}=\sqrt{4}*\sqrt{1245}=2\sqrt{1245}$$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{1245}}{2*-249}=\frac{0-2\sqrt{1245}}{-498} =-\frac{2\sqrt{1245}}{-498} =-\frac{\sqrt{1245}}{-249} $$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{1245}}{2*-249}=\frac{0+2\sqrt{1245}}{-498} =\frac{2\sqrt{1245}}{-498} =\frac{\sqrt{1245}}{-249} $
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