4(d+12)=68

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Solution for 4(d+12)=68 equation: 



4(d+12)=68

We move all terms to the left:

4(d+12)-(68)=0

We multiply parentheses

4d+48-68=0

We add all the numbers together, and all the variables

4d-20=0

We move all terms containing d to the left, all other terms to the right

4d=20

d=20/4

d=5

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