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5/2x=4x-9
We move all terms to the left:
5/2x-(4x-9)=0
Domain of the equation: 2x!=0We get rid of parentheses
x!=0/2
x!=0
x∈R
5/2x-4x+9=0
We multiply all the terms by the denominator
-4x*2x+9*2x+5=0
Wy multiply elements
-8x^2+18x+5=0
a = -8; b = 18; c = +5;
Δ = b2-4ac
Δ = 182-4·(-8)·5
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{484}=22$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-22}{2*-8}=\frac{-40}{-16} =2+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+22}{2*-8}=\frac{4}{-16} =-1/4 $
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