F(x)=(2x/2)+3

Solution for F(x)=(2x/2)+3 equation:

(F)=(2F/2)+3

We move all terms to the left:

(F)-((2F/2)+3)=0

We add all the numbers together, and all the variables

F-((+2F/2)+3)=0

We multiply all the terms by the denominator


F*2)+3)-((+2F=0

We add all the numbers together, and all the variables

2F+F*2)+3)-((=0

Wy multiply elements

2F^2+2F=0

a = 2; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·2·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*2}=\frac{-4}{4}
=-1
$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*2}=\frac{0}{4}
=0
$