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5/2x-8=6/x+3
We move all terms to the left:
5/2x-8-(6/x+3)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: x+3)!=0We get rid of parentheses
x∈R
5/2x-6/x-3-8=0
We calculate fractions
5x/2x^2+(-12x)/2x^2-3-8=0
We add all the numbers together, and all the variables
5x/2x^2+(-12x)/2x^2-11=0
We multiply all the terms by the denominator
5x+(-12x)-11*2x^2=0
Wy multiply elements
-22x^2+5x+(-12x)=0
We get rid of parentheses
-22x^2+5x-12x=0
We add all the numbers together, and all the variables
-22x^2-7x=0
a = -22; b = -7; c = 0;
Δ = b2-4ac
Δ = -72-4·(-22)·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-7}{2*-22}=\frac{0}{-44} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+7}{2*-22}=\frac{14}{-44} =-7/22 $
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