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5/2x+4=6x+4
We move all terms to the left:
5/2x+4-(6x+4)=0
Domain of the equation: 2x!=0We get rid of parentheses
x!=0/2
x!=0
x∈R
5/2x-6x-4+4=0
We multiply all the terms by the denominator
-6x*2x-4*2x+4*2x+5=0
Wy multiply elements
-12x^2-8x+8x+5=0
We add all the numbers together, and all the variables
-12x^2+5=0
a = -12; b = 0; c = +5;
Δ = b2-4ac
Δ = 02-4·(-12)·5
Δ = 240
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{240}=\sqrt{16*15}=\sqrt{16}*\sqrt{15}=4\sqrt{15}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{15}}{2*-12}=\frac{0-4\sqrt{15}}{-24} =-\frac{4\sqrt{15}}{-24} =-\frac{\sqrt{15}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{15}}{2*-12}=\frac{0+4\sqrt{15}}{-24} =\frac{4\sqrt{15}}{-24} =\frac{\sqrt{15}}{-6} $
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