5/2(8x+2)-3(x+5)-(x-4)=-6(2x-3)-3x+38

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Solution for 5/2(8x+2)-3(x+5)-(x-4)=-6(2x-3)-3x+38 equation: 



5/2(8x+2)-3(x+5)-(x-4)=-6(2x-3)-3x+38

We move all terms to the left:

5/2(8x+2)-3(x+5)-(x-4)-(-6(2x-3)-3x+38)=0



Domain of the equation: 2(8x+2)!=0

x∈R



We multiply parentheses

5/2(8x+2)-3x-(x-4)-(-6(2x-3)-3x+38)-15=0

We get rid of parentheses

5/2(8x+2)-3x-x-(-6(2x-3)-3x+38)+4-15=0

We multiply all the terms by the denominator


-3x*2(8x+2)-x*2(8x+2)-((-6(2x-3)-3x+38))*2(8x+2)+4*2(8x+2)-15*2(8x+2)+5=0



We calculate terms in parentheses: -((-6(2x-3)-3x+38))*2(8x+2), so:

(-6(2x-3)-3x+38))*2(8x+2



Wy multiply elements

-6x^2(8-2x^2(8-((-6(2x-3)-3x+38))*2(8x+2)+8x(8-30x(8+5=0

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