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3(5b-7)-8b=6(b-5)+2
We move all terms to the left:
3(5b-7)-8b-(6(b-5)+2)=0
We add all the numbers together, and all the variables
-8b+3(5b-7)-(6(b-5)+2)=0
We multiply parentheses
-8b+15b-(6(b-5)+2)-21=0
We calculate terms in parentheses: -(6(b-5)+2), so:We add all the numbers together, and all the variables
6(b-5)+2
We multiply parentheses
6b-30+2
We add all the numbers together, and all the variables
6b-28
Back to the equation:
-(6b-28)
7b-(6b-28)-21=0
We get rid of parentheses
7b-6b+28-21=0
We add all the numbers together, and all the variables
b+7=0
We move all terms containing b to the left, all other terms to the right
b=-7
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