5/2(6w-16)=18w(3w+40

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Solution for 5/2(6w-16)=18w(3w+40 equation: 



5/2(6w-16)=18w(3w+40

We move all terms to the left:

5/2(6w-16)-(18w(3w+40)=0



Domain of the equation: 2(6w-16)!=0

w∈R



We multiply all the terms by the denominator


-((18w(3w+40))*2(6w-16)+5=0

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