2d+1/6=6(3/1d+1)

Solution for 2d+1/6=6(3/1d+1) equation:

2d+1/6=6(3/1d+1)

We move all terms to the left:

2d+1/6-(6(3/1d+1))=0


Domain of the equation: 1d+1))!=0

d∈R


We calculate fractions


2d+()/d+d/d=0

Fractions to decimals

()/d+2d+1=0

We multiply all the terms by the denominator


2d*d+1*d+()=0

We add all the numbers together, and all the variables

d+2d*d=0

Wy multiply elements

2d^2+d=0

a = 2; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·2·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*2}=\frac{-2}{4}
=-1/2
$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*2}=\frac{0}{4}
=0
$