5/2(3j-13)=20

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Solution for 5/2(3j-13)=20 equation: 



5/2(3j-13)=20

We move all terms to the left:

5/2(3j-13)-(20)=0



Domain of the equation: 2(3j-13)!=0

j∈R



We multiply all the terms by the denominator


-20*2(3j-13)+5=0

Wy multiply elements

-40j(3+5=0

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