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5/1x-2=1x-5
We move all terms to the left:
5/1x-2-(1x-5)=0
Domain of the equation: 1x!=0We add all the numbers together, and all the variables
x∈R
5/1x-(x-5)-2=0
We get rid of parentheses
5/1x-x+5-2=0
We multiply all the terms by the denominator
-x*1x+5*1x-2*1x+5=0
Wy multiply elements
-1x^2+5x-2x+5=0
We add all the numbers together, and all the variables
-1x^2+3x+5=0
a = -1; b = 3; c = +5;
Δ = b2-4ac
Δ = 32-4·(-1)·5
Δ = 29
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{29}}{2*-1}=\frac{-3-\sqrt{29}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{29}}{2*-1}=\frac{-3+\sqrt{29}}{-2} $
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