5/(3x-5)=2/(x+1)

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Solution for 5/(3x-5)=2/(x+1) equation: 



5/(3x-5)=2/(x+1)

We move all terms to the left:

5/(3x-5)-(2/(x+1))=0



Domain of the equation: (3x-5)!=0

We move all terms containing x to the left, all other terms to the right

3x!=5

x!=5/3

x!=1+2/3

x∈R





Domain of the equation: (x+1))!=0

x∈R



We calculate fractions


5x/((3x-5)*(x+1)))+(-(2*(3x-5))/((3x-5)*(x+1)))=0



We calculate terms in parentheses: -(2*(3x-5))/((3x-5)*(x+1))), so:

2*(3x-5))/((3x-5)*(x+1))

We multiply all the terms by the denominator


2*(3x-5))

We multiply parentheses

6x+

We add all the numbers together, and all the variables

6x

Back to the equation:

-(6x)



We add all the numbers together, and all the variables

-6x+5x/((3x-5)*(x+1)))+(=0

We multiply all the terms by the denominator


-6x*((3x-5)*(x+1)))+(+5x=0

We add all the numbers together, and all the variables

5x-6x*((3x-5)*(x+1)))+(=0

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