2(2k-1)+4(3k+1=18

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Solution for 2(2k-1)+4(3k+1=18 equation: 



2(2k-1)+4(3k+1=18

We move all terms to the left:

2(2k-1)+4(3k+1-(18)=0

We multiply parentheses

4k+4(3k+1-18-2=0

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