5/(3x+1)=2

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Solution for 5/(3x+1)=2 equation: 



5/(3x+1)=2

We move all terms to the left:

5/(3x+1)-(2)=0



Domain of the equation: (3x+1)!=0

We move all terms containing x to the left, all other terms to the right

3x!=-1

x!=-1/3

x!=-1/3

x∈R



We multiply all the terms by the denominator


-2*(3x+1)+5=0

We multiply parentheses

-6x-2+5=0

We add all the numbers together, and all the variables

-6x+3=0

We move all terms containing x to the left, all other terms to the right

-6x=-3

x=-3/-6

x=1/2

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