64=4+(4x+2)

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Solution for 64=4+(4x+2) equation:



64=4+(4x+2)
We move all terms to the left:
64-(4+(4x+2))=0
We calculate terms in parentheses: -(4+(4x+2)), so:
4+(4x+2)
determiningTheFunctionDomain (4x+2)+4
We get rid of parentheses
4x+2+4
We add all the numbers together, and all the variables
4x+6
Back to the equation:
-(4x+6)
We get rid of parentheses
-4x-6+64=0
We add all the numbers together, and all the variables
-4x+58=0
We move all terms containing x to the left, all other terms to the right
-4x=-58
x=-58/-4
x=14+1/2

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