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5-3x(2x-1)=0
We multiply parentheses
-6x^2+3x+5=0
a = -6; b = 3; c = +5;
Δ = b2-4ac
Δ = 32-4·(-6)·5
Δ = 129
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{129}}{2*-6}=\frac{-3-\sqrt{129}}{-12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{129}}{2*-6}=\frac{-3+\sqrt{129}}{-12} $
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