3(2x-4)=2(x-3)+2

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Solution for 3(2x-4)=2(x-3)+2 equation: 



3(2x-4)=2(x-3)+2

We move all terms to the left:

3(2x-4)-(2(x-3)+2)=0

We multiply parentheses

6x-(2(x-3)+2)-12=0



We calculate terms in parentheses: -(2(x-3)+2), so:

2(x-3)+2

We multiply parentheses

2x-6+2

We add all the numbers together, and all the variables

2x-4

Back to the equation:

-(2x-4)



We get rid of parentheses

6x-2x+4-12=0

We add all the numbers together, and all the variables

4x-8=0

We move all terms containing x to the left, all other terms to the right

4x=8

x=8/4

x=2

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