2(6z+5)=-2(2z+3)

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Solution for 2(6z+5)=-2(2z+3) equation: 



2(6z+5)=-2(2z+3)

We move all terms to the left:

2(6z+5)-(-2(2z+3))=0

We multiply parentheses

12z-(-2(2z+3))+10=0



We calculate terms in parentheses: -(-2(2z+3)), so:

-2(2z+3)

We multiply parentheses

-4z-6

Back to the equation:

-(-4z-6)



We get rid of parentheses

12z+4z+6+10=0

We add all the numbers together, and all the variables

16z+16=0

We move all terms containing z to the left, all other terms to the right

16z=-16

z=-16/16

z=-1

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