5-3(2x-7)=12-5(x-2)

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Solution for 5-3(2x-7)=12-5(x-2) equation: 



5-3(2x-7)=12-5(x-2)

We move all terms to the left:

5-3(2x-7)-(12-5(x-2))=0

We multiply parentheses

-6x-(12-5(x-2))+21+5=0



We calculate terms in parentheses: -(12-5(x-2)), so:

12-5(x-2)

determiningTheFunctionDomain
-5(x-2)+12

We multiply parentheses

-5x+10+12

We add all the numbers together, and all the variables

-5x+22

Back to the equation:

-(-5x+22)



We add all the numbers together, and all the variables

-6x-(-5x+22)+26=0

We get rid of parentheses

-6x+5x-22+26=0

We add all the numbers together, and all the variables

-1x+4=0

We move all terms containing x to the left, all other terms to the right

-x=-4

x=-4/-1

x=+4

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