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-1/5(5y+2)-3/10(-4y-4)=8/5
We move all terms to the left:
-1/5(5y+2)-3/10(-4y-4)-(8/5)=0
Domain of the equation: 5(5y+2)!=0
y∈R
Domain of the equation: 10(-4y-4)!=0We add all the numbers together, and all the variables
y∈R
-1/5(5y+2)-3/10(-4y-4)-(+8/5)=0
We get rid of parentheses
-1/5(5y+2)-3/10(-4y-4)-8/5=0
We calculate fractions
(-10y(-)/(5(5y+2)*10(-4y-4)*5)+(-75y5/(5(5y+2)*10(-4y-4)*5)+(-80y(-)/(5(5y+2)*10(-4y-4)*5)=0
We calculate terms in parentheses: +(-10y(-)/(5(5y+2)*10(-4y-4)*5)+(-75y5/(5(5y+2)*10(-4y-4)*5)+(-80y(-)/(5(5y+2)*10(-4y-4)*5), so:
-10y(-)/(5(5y+2)*10(-4y-4)*5)+(-75y5/(5(5y+2)*10(-4y-4)*5)+(-80y(-)/(5(5y+2)*10(-4y-4)*5
We can not solve this equation
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