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5-2(3x+4)=3-4(2x+1)
We move all terms to the left:
5-2(3x+4)-(3-4(2x+1))=0
We multiply parentheses
-6x-(3-4(2x+1))-8+5=0
We calculate terms in parentheses: -(3-4(2x+1)), so:We add all the numbers together, and all the variables
3-4(2x+1)
determiningTheFunctionDomain -4(2x+1)+3
We multiply parentheses
-8x-4+3
We add all the numbers together, and all the variables
-8x-1
Back to the equation:
-(-8x-1)
-6x-(-8x-1)-3=0
We get rid of parentheses
-6x+8x+1-3=0
We add all the numbers together, and all the variables
2x-2=0
We move all terms containing x to the left, all other terms to the right
2x=2
x=2/2
x=1
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