3(4x+1)=99

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Solution for 3(4x+1)=99 equation: 



3(4x+1)=99

We move all terms to the left:

3(4x+1)-(99)=0

We multiply parentheses

12x+3-99=0

We add all the numbers together, and all the variables

12x-96=0

We move all terms containing x to the left, all other terms to the right

12x=96

x=96/12

x=8

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