3(4x+-5)=10x+29

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Solution for 3(4x+-5)=10x+29 equation: 



3(4x+-5)=10x+29

We move all terms to the left:

3(4x+-5)-(10x+29)=0

We add all the numbers together, and all the variables

3(4x-5)-(10x+29)=0

We multiply parentheses

12x-(10x+29)-15=0

We get rid of parentheses

12x-10x-29-15=0

We add all the numbers together, and all the variables

2x-44=0

We move all terms containing x to the left, all other terms to the right

2x=44

x=44/2

x=22

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