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5-1/2x=5/8x-12
We move all terms to the left:
5-1/2x-(5/8x-12)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 8x-12)!=0We get rid of parentheses
x∈R
-1/2x-5/8x+12+5=0
We calculate fractions
(-8x)/16x^2+(-10x)/16x^2+12+5=0
We add all the numbers together, and all the variables
(-8x)/16x^2+(-10x)/16x^2+17=0
We multiply all the terms by the denominator
(-8x)+(-10x)+17*16x^2=0
Wy multiply elements
272x^2+(-8x)+(-10x)=0
We get rid of parentheses
272x^2-8x-10x=0
We add all the numbers together, and all the variables
272x^2-18x=0
a = 272; b = -18; c = 0;
Δ = b2-4ac
Δ = -182-4·272·0
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-18}{2*272}=\frac{0}{544} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+18}{2*272}=\frac{36}{544} =9/136 $
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