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4b=1/3b-15
We move all terms to the left:
4b-(1/3b-15)=0
Domain of the equation: 3b-15)!=0We get rid of parentheses
b∈R
4b-1/3b+15=0
We multiply all the terms by the denominator
4b*3b+15*3b-1=0
Wy multiply elements
12b^2+45b-1=0
a = 12; b = 45; c = -1;
Δ = b2-4ac
Δ = 452-4·12·(-1)
Δ = 2073
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-\sqrt{2073}}{2*12}=\frac{-45-\sqrt{2073}}{24} $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+\sqrt{2073}}{2*12}=\frac{-45+\sqrt{2073}}{24} $
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